The Great Big Book of Algebra

Sunday, November 30, 2008
Chapter One: Integer Poetry

"Adding Integers with Kitty"
One day while I was walking,
As happy as could be,
I noticed a little cat,
That happened to follow me.

I asked him what his name was,
And you know what? He could talk!
He said "My name is Kitty,
And I'll teach you how to walk!"

I told him that I knew how,
And although he looked quite sad,
He then cheered up and told me,
"Then I'll teach you how to add!"

I told him that I knew how once more,
But still,he offered to help,
He then wrote on a piece of paper,
And then I gave a little yelp!

He had added two negative integers,
Right before my eyes,
I could not believe it so I asked,
"Can I give it a try?"

He handed me the paper and pen,
And I gave it my best shot,
But sadly I could not add them,
Probably because I forgot!

Kitty was quite surprised at this,
However he showed me how,
To add integers quite easily,
And I can add them now!

"Subraction is Myth"
Subtracting is false
Adding opposites is true
Be true and go far

Partitive division,
Now what on earth is that?
Is it some form of writing,
Or a blue and purple hat?

I for one do not know,
What this could really mean,
Although I might've guessed,
That it might be for the keen.

Of course it is a long two words,
And the first is quite confusing!
This word I believe is just for those,
Who find such words amusing.

However it is not,
It is a form of math you'll see.
So now you know what "you know" means,
And I hope you'll let me be!

"A Man from a a Gown?"
There once was a man from a town,
Who did division while wearing a gown,
He was a bit crazy,
Some thought he was lazy,
Still, this did not make him frown.

"The Rules of Math"
Rules, rules, rules,
That's all I ever hear!
It's like I am surrounded,
By a herd of angry deer!

However in the math world,
The rules are really nice!
They bring me much enjoyment,
Kind of like a fuzzy dice.

The rules for multiplying,
Are really helpful too!
They make it easy to do a question,
And no more saying "Boo hoo!"

Oh yes these rules are something,
That I really like to obey,
These are in fact the only rules,
I listen to everyday!

Chapter Two: Combining Like Terms
and The Distributive Property


British Guy: Hello Governor!
Other Guy: What? Are you talking to me?
British Guy: Yes I am.
Other Guy: name's not Governor. It's Bob.
British Guy: Alright Bob... Do you know how to simplify n+3 -5n+12 by adding like terms?
Bob: Hey man I ain't in school no more! I can do that! It's -6n+15! How do you like dem apples!
British Guy: Well...personally I must say that dem apples are rotten! The answer is -4n+15! I thought you knew how to combine like terms!
Bob: Hey man! Don't be that way! I tried my best.
British Guy: Well your best isn't good enough! I must teach you how to combine like terms!
British Guy: To start you must reorder the integers and variables. To do this you must first circle the terms that you need to combine. In this expression you would circle 3n and -5n! Do you understand?
Bob: Yeah! I get it now!
British Guy: Good. The next step would be to reorder the integers and variables so that they are next to a like term. In this expression you would put n and -5n together and put 12 and 3 together. Are you with me so far?
Bob: I guess so...
British Guy: Alright...The final step in simplifying the expression is actually combining the terms. If you do this properly then you will get -4n+15. But, in your answer you probably thought that n equals negative one.
Bob: So, it doesn't equal negative one?
British Guy: No, it just equals one.
Bob: Cool...
British Guy: Alright. I have another expression for you to simplify. This time you must use the distributive property to solve it. The expression is 2 + 4 (3n+8)
Bob: I know what that is! It's that thing where you multiply the stuff in the brackets by what's kissing it right?
British Guy: Well...I don't know about kissing but...I guess so.
Bob: Yeah!!! I'm right! So...yeah... the answer is 12n+10!
British Guy: No, sorry Bob. That is incorrect. The answer is 12n+34
Bob: What!? How did you get that!?
British Guy: Well, you have to multiply what's in the brackets by what's...kissing...the brackets. In this expression you would multiply both 3n and 8 by 4 because that's what's touching the brackets.
Bob: Oh! So you have to multiply both numbers by 4! I didn't know that!
British Guy: Well now you do!
Bob: Thanks man! Hey, I never did get your name. What is it?
British Guy: My name? Well...I can't tell you that!!!
Bob: Why? Please tell me! I told you mine!
British Guy: name is...Petunia Louise... Don't laugh...
Bob: Hey man! Don't sweat it! That's an awesome name! In fact, it's also my mom's name!
Petunia Louise: ...Oh my...


Chapter Three: One Step Equation Solving

Have you ever wanted to solve algebraic equations? Do you want to be able to show off in math class? Do you even know what algebraic equations are? If you want to know the answer to these questions then you must know the acronym ICOBV! Now, you're probably thinking "What's that weird word supposed to do for me?" but I can tell you that if you know this then you can solve any one step algebraic equation that you want. By the way, ICOBV stands for:

Isolate the variable by
Cancelling using the

This equation can be used to solve any kind of one step equation that you come across. Now, allow me to show you how to use ICOBV to solve the following questions.


I'll start with addition because I'm pretty sure everyone is very comfortable with it. The question will be... (note: just click the image to make it larger).

Now that you know how to do one step algebraic addition questions you'll find that subtraction questions are very similar. The question is...


Now we're in the big league. Many people get scared when someone says multiplication but I assure you that ICOBV will still come through for us.

Now we're at division, the last question. Division is just the opposite of multiplication and as such you'll find many similarities to the two.

Congratulations! You can now solve one step algebraic equations! Or, if not, then I suggest that you read this post again.
Chapter Four: One Step Equation Solving
with Algebra Tiles

Scribe post for Nov.26

Wednesday, November 26, 2008
Hey guys ! Today in class we did a QUIZ!

We had 10 questions as usual, and we had 20 minutes to do them.
Our first question was..

As we all should know , -3+(-5)=-8 and (-8)-(11)= ----->-19<-----


Now, (5)(-4)=-20 & (-2)(-1)=(2)(-6)=-12


6(-2)= -12 & (-3)(1)=-3
(-12)(-3)=36 & -3(3)=-9


(-5+19)= 14 & 6(-1)=-6



Well, I guess that is it because Mr. Harbeck told me to do the first 4 questions! (:
Anyways.. yeeaah, BYE & comment like crazy!
Oh right , and the scribe for monday is .. KEVIN ! haha. >x)

Scribe For November 25, 2008

Tuesday, November 25, 2008
What We Did...

Today in math we just review dividing integers...

Yeah... It's due tomorrow. Both SIDES should be done if you want a good mark... For example the ++ side should have these things:


(Sigh...) We have some homework to do. We had to do the rest of page seven (question 19 and 23) Don't do the questions with exponents! Also We have to do question 1-15 on page 8. Here is one of them....

13 on page 8.
The answer is 23...( I think...) please correct me if I'm wrong...

Oh! There is a QUIZ tomorrow too!

Don't forget to study!

here are some of the questions on the quiz!

1.) -3+(-5)-11=



3.) __________ =


__________ =

The next scribe will be... Lara!

Scribe for November 24

Monday, November 24, 2008
Hey, Everybody! Today in class we did the last quadrant in our "barn".

The quadrant we did today was +-. Our question for today was positive 6 divided by negative 2.

First of all we had to write the question in the 4 ways we know how.

Next we have to write out the 2 statements that we know.

We found out that the quotative and partitive ways do not work because we cannot make groups of -2 when we have 6.

So, we found another way to solve this question. By using .... multiplicative inverse! This will solve the question without grouping the integers.

Therefore, our answer will be negative three.


For homework, we had to do page 7 in the green booklet. Questions 10-17.

Mr. Harbeck Told us to:

And for those of you who need a little jump start in your homework, I will get you started with a few questions.

And for scribe tommorow, I choose.... Kim C

Scribe Post November 21/08

Friday, November 21, 2008
Hey guys! Today in class we reviewed the "barn door" that shows us how to divide negative and negative integers. In the barn door that expresses us how to divide negative and negative integers we did another question. The question was 12/4.

First we had to express it in two different ways.

Next we had to make a QUOTATIVE and PARTITIVE questions and draw pictures. Quotative does not work for this question.

Quotative does not work for that question because you can not make groups of positive 4s in negative 12 and the answer for that question is 3.

For the fourth quadrant we had to do the question 6/-2, we had to express it in two different ways:

For homework we had to do questions 1-9 in the green booklet. We had to pick 6 questions that fits into our barns, draw 3 of them and do the multiplicative inverse for all of them. We also have to put the quotative and partitive sentences with the question. We have to put it in our notebooks.

Here is an answer for one of the nine questions we had to answer:

The next scribe shall be JOYSIE!

Scribe November 20th, 2008

Thursday, November 20, 2008
In today's class we got a review of how to divide positive and positive integers. If you scroll down, you can see Karen's scribe to get a re-cap.
In our barns we learned about dividing negative and positive integers. The question we started off with was:
The answer to this questions is -3 but how can we solve this question with the Quotative and the Partitive?

For the Quotative it is asking us: How many positive twos are in negative six?
As you can see, it is all negatives. If your thinking zero pairs, you are wrong. We do not need zero pairs for this because we are already given negative six.

So how do we solve this question?

The Partitive asks us: How many equal parts are in 2 groups when we have -6?
See? The answer is -3 which is exactly what we needed. Remember that the Partitive is just like dealing cards in real life because we have to deal the cards equally to each person.
So in short, using the Quotative will not give you the answer for dividing a negative and positive integer.

Our homework is to put the quotative or partitive to solve -6 *divided by* -2 on the negative (--) negative boxes of The Barn.

the next scribe shall be nikslops!

Scribe Post for November 19 2008

Wednesday, November 19, 2008
Today in class we started learning about dividing integers. Mr. Harbeck and Mr. Backe (sorry if I spelt it wrong) taught us dividing positive integers. We flipped our 'barns' to the white side which is division.

We did the positive positive side (++).
The question is:
This question can be said in 2 ways.
1st way: (QUOTATIVE) How many 2s are in 6?
2nd way (PARTITIVE) How many equal parts are in 2 groups when we have 6?




Here's a video about dividing integers.

That's what we did in math today. Homework for Mr. Backe ( and again sorry if I spelt it wrong ): ) is to think about this question- ___x 2 = 6

I pick Gizzle to be the next scribe!

Scribe Post for November 18 2008

Tuesday, November 18, 2008
In class today, we didn't do very much. We were given a quiz consisting of 10 questions. We were all instructed to show our work. Since we were to hand in the quiz following the completion, I cannot talk about each of the questions. But what I will do is refresh your eager minds about boxing (the "Green" way, and "Blue" way), adding integers, and subtracting integers. I will, because that's what the math quiz that we did was all about.

Do you remember how to add integers? Hopefully, you do. Here is a very simple example.
(+2) + (+3)
Since the integers are both positive, you would use standard math to answer this question. Although, standard math is probably the ideal method to use, but there are other ways to solve questions such as these, as well. The other methods are using integer tiles, number lines, and have and owe.
So, did you figure out the answer ? Yup, I knew you did. The answer is (+5)

Now, let's see if you remember subtracting negative integers, shall we? Here is a simple question. Try solving it. Keep in mind, you never really subtract. When you see a negative sign, you switch the sign to a negative, and the next integer sign to the opposite sign.
(+2) - (+3)
(+2) + (-3)
When subtracting integers, it is useful to use a number line. Remember, a number line has a ZERO in the middle, and infinite positive numbers to the right, and infinite negative numbers to the left. When subtracting integers, you would move that many places to the left. The same rule applies to adding positive integers, except you would move to the right, instead of the left.

Alright now, we should remember this number line method by now. Below, is the Have and Owe method.

Now, I'll be talking about the recent things we have learned, which is multiplying integers.
Remember, when the brackets are touching, they multiply! Keep in mind the ROOM 17 Theorem !
"When you multiply an odd amount of negatives, the product is always negative"
(the amount of positives in the question won't affect the product)

When you multiply a negative, and a negative, the product is always positive.
When you multiply a positive, and a negative, the product is always negative.
When you multiply a positive, and a positive, the product is always positive.
When you multiply a negative, and a positive, the product is always negative.

Here is a fairly simple example.
(2)(-3) = (-6)
The answer is (-6) because a positive and a negative equals a negative, and 2 multiplied by 3 equals 6.

Now, I'll talk about boxing, the BLUE way.
Here is an example using brackets.

Now, I hope that the picture above is helpful to you all. Using the "blue" method, you box out the group of integers, that you will multiply. In the group of integers, you multiply the integers to get 1 answer. Then, once you have your answers for the boxed out integers, you bring down the order of operations.

Now, I'll talk about the Green method. Using the green method, you put a (1) by the order of operations, if its an adding sign. You put a (-1) if its a subtraction sign. Below is a picture explaining the who "Green Method" idea.Sorry if I did the Green Method wrong. I wasn't absolutely sure how to do it...
Karen, I choose YOU ! (as the next scribe)
Here is a video of adding integers

Here is a video of subtracting integers

Here is a video of multiplying integers

Nov. 17/08 Scribe Post!!

Monday, November 17, 2008
Today Mr. Herbeck isn't here so he made a video on the . Today we only need to check are last test in Math class.
On the video that Mr. Herbeck made, he was telling us how to do the new multiplying Integers. Today I'm going to show you how to do in 2 ways.

[2 Ways]
Integer question in use - (-4) (-1) (-2) - (1) (6) (3) + (-4) (-5) (-3) =

Way number 1:

Sorry if my answer is wrong =[

Way number 2:

Again, sorry if this confuse you.

Another Thing after this explaining:
After When Mr. Herbeck told us how to do the questions, we got are test back to check. After when your done checking are test, Mr. Herbeck said Correct your answers on the video. Like if you get this answer wrong you can correct it.

Today Homework you have to do the Green book 6 and the yellow book 51. You also have to show your work. Green book do the whole thing 1 - 18. Also on the yellow book, I think your suppose to do all of it.

Green Book!!

Yellow Book!!

That is all for Today class Nov. 17/08
I Choose Linda Duck for Scribe!!!!!!!!!!!

Scribe Post

Friday, November 14, 2008
Today, we learned new stuff in Math and lets go over it! Now for some new stuff..
(2)(-3)+(2)(-3)=?? Now lets solve this question.Now for another question. (-2)(3)+2(-3)-6(1)+(3)(4)=??
Remember to solve the brackets first and pull down the order of operations after.
And that's what we did in Math! For homework you need to work on the questions 1to7 on page 6.

Nov.13 Scribe Post

Thursday, November 13, 2008

Today in class we talked about multiplying integers again.

We made a theory for these integers

1.(-)(-)= 5.(+)(-)=

2.(-)(-)(-)= 6.(+)(-)(-)=

3.(-)(-)(-)(-)= 7 .(+)(-)(-)(-)(-)=

4.(-)(-)(-)(-)(-)= 4(+)(-)(-)(-)(-)(-)=

1. When you multiply an even amount of negative integer the product is a positive integer.

2. When you multiply an odd amount of negative integers the product is a negative integer.

So after those rules it would be.

1.(-)(-)= (+) 5.(+)(-)= (+)

2.(-)(-)(-)= (-) 6.(+)(-)(-)= (-)

3.(-)(-)(-)(-)= (+) 7 .(+)(-)(-)(-)(-)= (+)

4.(-)(-)(-)(-)(-)= (-) 4(+)(-)(-)(-)(-)(-)= (-)

One of the questions we did during class was


You can’t multiply nothing so you needed to add “Zero Pairs”. How I did the question I split the whole question in 2 parts.

eg. (-1)(-2) = 2

(-2)(-1) = 2

Together is would be (+2) (+2) now, this question would say 2 groups of +2.

The answer is 4.

We were assigned to do some practice on it. For our practice, we had to page five, questions 19 to 36.

Here are some questions and answers.

36. -12(8) (-5) (0) (-7) =0

The answer would be 0 because it doesn’t matter where the 0 is in the question it will automatically be a 0

22. 3(-5) (4) = (-60)

I split the question to [3(-5)] (4), I did the square brackets first. The question inside says 3 groups of -5 that would be -15.After that the question would look like


That question says now remove 15 groups of 4. What’s left when you move 15 groups of 4 from the zero pairs would be -60.

I choose Liem to be the next scribe. HAHAHAHA

Scribe Post for November 12

Wednesday, November 12, 2008
Today in math class we went over some homework. One of the questions we did was this one:
This means take away five groups of 4. Since you cant take away 5 groups of negitive 4 you have to make zero pairs.

Once you take away five groups of zero pairs it should look like this:The answer is 20.

Now for todays work. We went over some rules on multiplying integers. Here are those rules.

When you multiply an even amount of negitive integers the product is always a postive product. Another one is when you multiply an odd number of negative integers the product is always a negitive product.


Homework for today.

Todays homework we had to Prove the room 17 theorem with questions 13-18 in the green book. This is what I did. Well I just answered all the questions. I didn't really get this homework, but I tried.

I choose Robin to be the next scribe. HAHAHAHA

Scribe Post For November, 10. 2008

Monday, November 10, 2008
Today in class we talked about multiplying integers again. But instead of adding more things to our booklet with two sides on it, we were assigned to do some practice on it. For our practice, we had to page five, questions one to twelve, and what patterns we see on questions thirteen and fourteen. We also had to pick four questions out of the 12 questions that we had to do and draw a diagram to support our answer. Then we were asked to make a rule on what the product will be when we multiply certain integers together. It kind of looked like this....

Make a rule!

When I multiply.....

1.(-)(-)= 5.(+)(-)=

2.(-)(-)(-)= 6.(+)(-)(-)=

3.(-)(-)(-)(-)= 7 .(+)(-)(-)(-)(-)=


If you can't figure out what it is these are the answers.

1. +
2. -
3. +
4. -
5. +
6. +
7. -

These are some of the questions and answers for the questions in the green booklet.

1. (3)(9)=27

This question equals to this answer because the answer is just simply saying what is 3 times nine.

2. (-11)(4)= (-44)

This question equals to this answer because a negative times a positive always equals a negative product. So the first thing you do is multiply eleven and 4 together and then change that answer into a negative answer.

3. (-4)(-12)=48

This question equals to this answer because a negative multiplied by a negative will always become a positive product. The first thing that you do to solve this question is change the negative integers into a positive integer and then multiply.

4. (8)(-8)=(-64)

This question equals to this answer because when you multiply a positive integer to a negative you will alwaysd get a negative product. To solve this question all you have to do is what i said in question 2.

5. (6)(-2)=(-12)

This question equals to this answer because of what i said in question 4.

The Carlo Scribe II

Thursday, November 6, 2008
Mwhahahahaha do you remember what we did at class do ya? Well I know what we did in class, we did a test today for 15 minutes with ten questions it was kind of easy, but for other people it was hard for them, if you were the people who got the answer quickly, hooray for you. After the test was completed you have to get a little sentence at the back of the paper on how well you did. After the test we have to complete the "multiplacation of integers" paper with Mr. Backe.

We have to finish positive and negative logo and negative and negative logo. Before that we have to make sentences to match with the logos. For negative and positive logo we put, When I multiply a negative integer with a positive integer the product is always a negative product. For positive and positive logo we put, When I multiply a positve integer with a positive integer it is always a positive product. Do you get it so far, yeah I bet you do.

Now if you open the blue flap at the right side in the bottom you shall get the logo that looks like a positive integer with a negative integer, if you didn't do that it must be somewhere in the blue squares. Now he gave us some examples, they were (+3)(-2) am I correct. Then we simply just multiply it and used algebra tiles to help us. Now if you look at the bottom of the paragraph you"ll see an example of the math we just did an you know how I do.

Now this question is like the negative and positive one but it gets switched around. If you don't get the problem look at the picture underneath the paragraph.

Do you get what I mean you just have to have a zero pair to remove three groups of negative two.... I think...or three pairs of Marios..... Then when we done that we have to go to the logo that says negative and negative. Now he wrote an example simular to the other ones he wrote

(-2)(-3) yeah am I correct. Now for this question y'all have to make the algebra tiles out of nowhere again. Then do the math now I put pictures and hints to do it. Look underneath the paragraph!

Now for the next step but this time I'm not using Mario for it this time its a pink puffball. If you want to under stand the problem clearly. Just look under dudes and dudettes.

Okay now you under stand that you take away the blue Kirby(negative) instead of the pink one (postive) that means that y'all have to do the oppposite thing than the normal ones. Then after that y'all have to do homework, well I'm done my homework at school, my questions were

(-12)(-10) and (+12)(-5) and showed pictures and words. That made me forgot the sentences that matches the logos are, When I multiply a negative integer with another negative integer the product will always be positive. Then for the last one is, When I multiply as positve integer with a negative integer the product will always be negative. But if you do my homework questions it will be insane to do, just do normal ones. I chose that question so I could fit it in my page if your wondering. Yeah that is my post, uhhhhmm now you may do anything to it if I have any grammer or normal mistakes, now I do my leave har har har har har har har har har har har!!!!