Math Blog 817 (2008)
Tuesday, June 2, 2009
Tanner`s Percent Post
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Mr. Harbeck asked us to make a post with questions off of a sheet we did in class. We had to do five questions, three from part A and any tw...
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Monday, June 1, 2009
Jowella's Percent Post
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For this post, I chose to answer 5 questions from the paper that Mr.Harbeck gave to us during math class. Here are the five questions that...
Nicky's Percent Post
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Part A Part B
1 comment:
Sunday, May 31, 2009
Linda's Percent Post
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Hello everyone! Mr. H assigned us all a post answering a few percent questions, and here is mine. Feel free to leave a comment! The first ...
1 comment:
Percent Post
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Part A 1) 245% of $356.80 The easiest way to solve this question is to use a ratio table . The question is what is 245% of $365.80? $365.80 ...
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Part A -- 1) 245% of $356.80 356.80 / 10 = 35.68 (10%) 35.68 / 2 = 17.84 245% of $356.80 is $874.16 _______________________________________...
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Saturday, May 30, 2009
Percent Post
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Part A 1) 245% of $356.80 245% of $356.80 is $874.16 2) 68 3/4% of 730 3 *divided by* 4 = 0.75 68 3/4% = 68.75% 68 3/4% of 730 is 501...
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