Nov.13 Scribe Post

Thursday, November 13, 2008

Today in class we talked about multiplying integers again.

We made a theory for these integers

1.(-)(-)= 5.(+)(-)=

2.(-)(-)(-)= 6.(+)(-)(-)=

3.(-)(-)(-)(-)= 7 .(+)(-)(-)(-)(-)=

4.(-)(-)(-)(-)(-)= 4(+)(-)(-)(-)(-)(-)=


1. When you multiply an even amount of negative integer the product is a positive integer.


2. When you multiply an odd amount of negative integers the product is a negative integer.


So after those rules it would be.

1.(-)(-)= (+) 5.(+)(-)= (+)

2.(-)(-)(-)= (-) 6.(+)(-)(-)= (-)

3.(-)(-)(-)(-)= (+) 7 .(+)(-)(-)(-)(-)= (+)

4.(-)(-)(-)(-)(-)= (-) 4(+)(-)(-)(-)(-)(-)= (-)



One of the questions we did during class was

(-1)(-2)(-2)(-1)=

You can’t multiply nothing so you needed to add “Zero Pairs”. How I did the question I split the whole question in 2 parts.

eg. (-1)(-2) = 2

(-2)(-1) = 2

Together is would be (+2) (+2) now, this question would say 2 groups of +2.

The answer is 4.


We were assigned to do some practice on it. For our practice, we had to page five, questions 19 to 36.

Here are some questions and answers.


36. -12(8) (-5) (0) (-7) =0

The answer would be 0 because it doesn’t matter where the 0 is in the question it will automatically be a 0

22. 3(-5) (4) = (-60)

I split the question to [3(-5)] (4), I did the square brackets first. The question inside says 3 groups of -5 that would be -15.After that the question would look like

(-15)(4)

That question says now remove 15 groups of 4. What’s left when you move 15 groups of 4 from the zero pairs would be -60.

I choose Liem to be the next scribe. HAHAHAHA

5 comments:

  1. Breann 8-17 said...

    Great Job Robin. I didn't see any mistakes so very good job Robin.

    November 13, 2008 at 10:41 PM  

  2. Jocelynskogberg said...

    good work! The zero concept is a very important one and it will save you time!

    November 16, 2008 at 3:04 PM  

  3. Sara (U of R) said...

    Hey!
    Good post. I liked the way you wrote out the theories then gave the answer. It was good because it makes you think while you are reading them rather than stating and explaining the answers.
    A cool trick I like to use when I'm multiplying integers, which fits into your odd/even theory for negatives, is that two negative signs equals a plus sign (I mentally flip one on its end so it becomes vertical) and I just make plus signs until I am left with only plus signs or one negative sign. But I have to say, I like the odd/even thing way better! I don't think my teacher ever taught it to me that way.
    Nicely done! Keep it up. :)

    November 16, 2008 at 9:23 PM  

  4. alyannaL 8-17 said...

    Dear Robin Lorenzo,
    LOL ^^. Well I think you did a good job. But then you have some mistakes with your grammar and stuff. But I dont think Harbeck really cares about that. So anyways good job. (: And btw, I know your scribe post is old and was from before already. But then Harbeck said, to comment on the ones dont dont have any or at least that have fewer.

    November 24, 2008 at 6:58 PM  

  5. Mr. H said...

    Alyanna I do care. Thanks for commenting. Grammar is important. Perhaps one class should be spent on correcting old posts. Hmm thanks for making me think.

    November 24, 2008 at 7:00 PM  

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