817 Math Blog

Script

Other Guy: What? Are you talking to me?
British Guy: Yes I am.
Other Guy: Well...my name's not Governor. It's Bob.
British Guy: Alright Bob... Do you know how to simplify n+3 -5n+12 by adding like terms?
Bob: Hey man I ain't in school no more! I can do that! It's -6n+15! How do you like dem apples!
British Guy: Well...personally I must say that dem apples are rotten! The answer is -4n+15! I thought you knew how to combine like terms!
Bob: Hey man! Don't be that way! I tried my best.
British Guy: Well your best isn't good enough! I must teach you how to combine like terms!
British Guy: To start you must reorder the integers and variables. To do this you must first circle the terms that you need to combine. In this expression you would circle 3n and -5n! Do you understand?
Bob: Yeah! I get it now!
British Guy: Good. The next step would be to reorder the integers and variables so that they are next to a like term. In this expression you would put n and -5n together and put 12 and 3 together. Are you with me so far?
Bob: I guess so...
British Guy: Alright...The final step in simplifying the expression is actually combining the terms. If you do this properly then you will get -4n+15. But, in your answer you probably thought that n equals negative one.
Bob: So, it doesn't equal negative one?
British Guy: No, it just equals one.
Bob: Cool...
Bob: I know what that is! It's that thing where you multiply the stuff in the brackets by what's kissing it right?
British Guy: Well...I don't know about kissing but...I guess so.
Bob: Yeah!!! I'm right! So...yeah... the answer is 12n+10!
British Guy: No, sorry Bob. That is incorrect. The answer is 12n+34
Bob: What!? How did you get that!?
British Guy: Well, you have to multiply what's in the brackets by what's...kissing...the brackets. In this expression you would multiply both 3n and 8 by 4 because that's what's touching the brackets.
Bob: Oh! So you have to multiply both numbers by 4! I didn't know that!
British Guy: Well now you do!
Bob: Thanks man! Hey, I never did get your name. What is it?
British Guy: My name? Well...I can't tell you that!!!
Bob: Why? Please tell me! I told you mine!
British Guy: Alright...my name is...Petunia Louise... Don't laugh...
Bob: Hey man! Don't sweat it! That's an awesome name! In fact, it's also my mom's name!
Petunia Louise: ...Oh my...

Movie











This equation can be used to solve any kind of one step equation that you come across. Now, allow me to show you how to use ICOBV to solve the following questions.

Addition

Subtraction
Now that you know how to do one step algebraic addition questions you'll find that subtraction questions are very similar. The question is...

Multiplication

Now we're in the big league. Many people get scared when someone says multiplication but I assure you that ICOBV will still come through for us.

Division
Now we're at division, the last question. Division is just the opposite of multiplication and as such you'll find many similarities to the two.

Hey guys ! Today in class we did a QUIZ!

We had 10 questions as usual, and we had 20 minutes to do them.
Our first question was..

As we all should know , -3+(-5)=-8 and (-8)-(11)= ----->-19<-----

2)

Now, (5)(-4)=-20 & (-2)(-1)=(2)(-6)=-12
(-12)+(-20)=---->-32<-----

3)

6(-2)= -12 & (-3)(1)=-3
(-12)(-3)=36 & -3(3)=-9
(36)/(-9)=---->-4<-------

4)





(-5+19)= 14 & 6(-1)=-6

(14)+(-6)=8

8/-4=---->-2<-------

Well, I guess that is it because Mr. Harbeck told me to do the first 4 questions! (:
Anyways.. yeeaah, BYE & comment like crazy!
Oh right , and the scribe for monday is .. KEVIN ! haha. >x)

Yeah... It's due tomorrow. Both SIDES should be done if you want a good mark... For example the ++ side should have these things:

The quadrant we did today was +-. Our question for today was positive 6 divided by negative 2.

First of all we had to write the question in the 4 ways we know how.

Next we have to write out the 2 statements that we know.

We found out that the quotative and partitive ways do not work because we cannot make groups of -2 when we have 6.

So, we found another way to solve this question. By using .... multiplicative inverse! This will solve the question without grouping the integers.

Therefore, our answer will be negative three.

Homework

For homework, we had to do page 7 in the green booklet. Questions 10-17.

Mr. Harbeck Told us to:

And for those of you who need a little jump start in your homework, I will get you started with a few questions.

And for scribe tommorow, I choose.... Kim C

In today's class we got a review of how to divide positive and positive integers. If you scroll down, you can see Karen's scribe to get a re-cap.
In our barns we learned about dividing negative and positive integers. The question we started off with was:
The answer to this questions is -3 but how can we solve this question with the Quotative and the Partitive?

For the Quotative it is asking us: How many positive twos are in negative six?
As you can see, it is all negatives. If your thinking zero pairs, you are wrong. We do not need zero pairs for this because we are already given negative six.

So how do we solve this question?

The Partitive asks us: How many equal parts are in 2 groups when we have -6?
See? The answer is -3 which is exactly what we needed. Remember that the Partitive is just like dealing cards in real life because we have to deal the cards equally to each person.
So in short, using the Quotative will not give you the answer for dividing a negative and positive integer.

Our homework is to put the quotative or partitive to solve -6 *divided by* -2 on the negative (--) negative boxes of The Barn.

the next scribe shall be nikslops!

Today in class we started learning about dividing integers. Mr. Harbeck and Mr. Backe (sorry if I spelt it wrong) taught us dividing positive integers. We flipped our 'barns' to the white side which is division.


We did the positive positive side (++).
The question is:
This question can be said in 2 ways.
1st way: (QUOTATIVE) How many 2s are in 6?
2nd way (PARTITIVE) How many equal parts are in 2 groups when we have 6?



ANOTHER WAY YOU CAN WRITE THIS QUESTION:







QUOTATIVE:










PARTITIVE:













Here's a video about dividing integers.




That's what we did in math today. Homework for Mr. Backe ( and again sorry if I spelt it wrong ): ) is to think about this question- ___x 2 = 6



I pick Gizzle to be the next scribe!

In class today, we didn't do very much. We were given a quiz consisting of 10 questions. We were all instructed to show our work. Since we were to hand in the quiz following the completion, I cannot talk about each of the questions. But what I will do is refresh your eager minds about boxing (the "Green" way, and "Blue" way), adding integers, and subtracting integers. I will, because that's what the math quiz that we did was all about.

Do you remember how to add integers? Hopefully, you do. Here is a very simple example.
(+2) + (+3)
Since the integers are both positive, you would use standard math to answer this question. Although, standard math is probably the ideal method to use, but there are other ways to solve questions such as these, as well. The other methods are using integer tiles, number lines, and have and owe.
So, did you figure out the answer ? Yup, I knew you did. The answer is (+5)

Now, let's see if you remember subtracting negative integers, shall we? Here is a simple question. Try solving it. Keep in mind, you never really subtract. When you see a negative sign, you switch the sign to a negative, and the next integer sign to the opposite sign.
(+2) - (+3)
(+2) + (-3)
When subtracting integers, it is useful to use a number line. Remember, a number line has a ZERO in the middle, and infinite positive numbers to the right, and infinite negative numbers to the left. When subtracting integers, you would move that many places to the left. The same rule applies to adding positive integers, except you would move to the right, instead of the left.

Alright now, we should remember this number line method by now. Below, is the Have and Owe method.


Now, I'll be talking about the recent things we have learned, which is multiplying integers.
Remember, when the brackets are touching, they multiply! Keep in mind the ROOM 17 Theorem !
"When you multiply an odd amount of negatives, the product is always negative"
(the amount of positives in the question won't affect the product)

When you multiply a negative, and a negative, the product is always positive.
When you multiply a positive, and a negative, the product is always negative.
When you multiply a positive, and a positive, the product is always positive.
When you multiply a negative, and a positive, the product is always negative.

Here is a fairly simple example.
(2)(-3) = (-6)
The answer is (-6) because a positive and a negative equals a negative, and 2 multiplied by 3 equals 6.

Now, I'll talk about boxing, the BLUE way.
Here is an example using brackets.


Now, I hope that the picture above is helpful to you all. Using the "blue" method, you box out the group of integers, that you will multiply. In the group of integers, you multiply the integers to get 1 answer. Then, once you have your answers for the boxed out integers, you bring down the order of operations.

Now, I'll talk about the Green method. Using the green method, you put a (1) by the order of operations, if its an adding sign. You put a (-1) if its a subtraction sign. Below is a picture explaining the who "Green Method" idea.Sorry if I did the Green Method wrong. I wasn't absolutely sure how to do it...
Karen, I choose YOU ! (as the next scribe)
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Here is a video of adding integers






Here is a video of subtracting integers




Here is a video of multiplying integers

Today Mr. Herbeck isn't here so he made a video on the http://www.sargentparkmathzone.blogspot.com/ . Today we only need to check are last test in Math class.
On the video that Mr. Herbeck made, he was telling us how to do the new multiplying Integers. Today I'm going to show you how to do in 2 ways.

Today in class we talked about multiplying integers again.

We made a theory for these integers

1.(-)(-)= 5.(+)(-)=

2.(-)(-)(-)= 6.(+)(-)(-)=

3.(-)(-)(-)(-)= 7 .(+)(-)(-)(-)(-)=

4.(-)(-)(-)(-)(-)= 4(+)(-)(-)(-)(-)(-)=

1. When you multiply an even amount of negative integer the product is a positive integer.

2. When you multiply an odd amount of negative integers the product is a negative integer.

So after those rules it would be.

1.(-)(-)= (+) 5.(+)(-)= (+)

2.(-)(-)(-)= (-) 6.(+)(-)(-)= (-)

3.(-)(-)(-)(-)= (+) 7 .(+)(-)(-)(-)(-)= (+)

4.(-)(-)(-)(-)(-)= (-) 4(+)(-)(-)(-)(-)(-)= (-)

One of the questions we did during class was

(-1)(-2)(-2)(-1)=

You can’t multiply nothing so you needed to add “Zero Pairs”. How I did the question I split the whole question in 2 parts.

eg. (-1)(-2) = 2

(-2)(-1) = 2

Together is would be (+2) (+2) now, this question would say 2 groups of +2.

The answer is 4.

We were assigned to do some practice on it. For our practice, we had to page five, questions 19 to 36.

Here are some questions and answers.

36. -12(8) (-5) (0) (-7) =0

The answer would be 0 because it doesn’t matter where the 0 is in the question it will automatically be a 0

22. 3(-5) (4) = (-60)

I split the question to [3(-5)] (4), I did the square brackets first. The question inside says 3 groups of -5 that would be -15.After that the question would look like

(-15)(4)

That question says now remove 15 groups of 4. What’s left when you move 15 groups of 4 from the zero pairs would be -60.

I choose Liem to be the next scribe. HAHAHAHA

Today in math class we went over some homework. One of the questions we did was this one:

Homework for today.

Todays homework we had to Prove the room 17 theorem with questions 13-18 in the green book. This is what I did. Well I just answered all the questions. I didn't really get this homework, but I tried.

I choose Robin to be the next scribe. HAHAHAHA

Today in class we talked about multiplying integers again. But instead of adding more things to our booklet with two sides on it, we were assigned to do some practice on it. For our practice, we had to page five, questions one to twelve, and what patterns we see on questions thirteen and fourteen. We also had to pick four questions out of the 12 questions that we had to do and draw a diagram to support our answer. Then we were asked to make a rule on what the product will be when we multiply certain integers together. It kind of looked like this....

Make a rule!

When I multiply.....

1.(-)(-)= 5.(+)(-)=

2.(-)(-)(-)= 6.(+)(-)(-)=

3.(-)(-)(-)(-)= 7 .(+)(-)(-)(-)(-)=

4.(-)(-)(-)(-)(-)=

If you can't figure out what it is these are the answers.

1. +
2. -
3. +
4. -
5. +
6. +
7. -

These are some of the questions and answers for the questions in the green booklet.

1. (3)(9)=27

This question equals to this answer because the answer is just simply saying what is 3 times nine.

2. (-11)(4)= (-44)

This question equals to this answer because a negative times a positive always equals a negative product. So the first thing you do is multiply eleven and 4 together and then change that answer into a negative answer.

3. (-4)(-12)=48

This question equals to this answer because a negative multiplied by a negative will always become a positive product. The first thing that you do to solve this question is change the negative integers into a positive integer and then multiply.

4. (8)(-8)=(-64)

This question equals to this answer because when you multiply a positive integer to a negative you will alwaysd get a negative product. To solve this question all you have to do is what i said in question 2.

5. (6)(-2)=(-12)

This question equals to this answer because of what i said in question 4.